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For the following list:
test_list = ['one', 'two','threefour']
How would I find out if an item starts with 'three' or ends with 'four' ?
For example, instead of testing membership like this:
two in test_list
I want to test it like this:
startswith('three') in test_list.
How would I accomplish this?
660
Use the in operator for partial matches, i.e., whether one string contains the other string. x in y returns True if x is contained in y ( x is a substring of y ), and False if it is not. If each character of x is contained in y discretely, False is returned.
In python programming we can check whether strings are equal or not using the “==” or by using the “. __eq__” function. Example: s1 = 'String' s2 = 'String' s3 = 'string' # case sensitive equals check if s1 == s2: print('s1 and s2 are equal.
Python Find String in List using count() We can also use count() function to get the number of occurrences of a string in the list. If its output is 0, then it means that string is not present in the list. l1 = ['A', 'B', 'C', 'D', 'A', 'A', 'C'] s = 'A' count = l1.
A partial matching is a collection A of arcs with the requirement that each vertex is contained in at most one arc.
You can use any():
any(s.startswith('three') for s in test_list)
You could use one of these:
>>> [e for e in test_list if e.startswith('three') or e.endswith('four')]
['threefour']
>>> any(e for e in test_list if e.startswith('three') or e.endswith('four'))
True
http://www.faqs.org/docs/diveintopython/regression_filter.html should help.
test_list = ['one', 'two','threefour']
def filtah(x):
return x.startswith('three') or x.endswith('four')
newlist = filter(filtah, test_list)
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