Python list directory, subdirectory, and files

Question

I'm trying to make a script to list all directory, subdirectory, and files in a given directory.
I tried this:

import sys,os  root = "/home/patate/directory/" path = os.path.join(root, "targetdirectory")  for r,d,f in os.walk(path):     for file in f:         print os.path.join(root,file) 

Unfortunatly it doesn't work properly.
I get all the files, but not their complete paths.

For example if the dir struct would be:

 /home/patate/directory/targetdirectory/123/456/789/file.txt 

It would print:

 /home/patate/directory/targetdirectory/file.txt 

What I need is the first result. Any help would be greatly appreciated! Thanks.

Answer 1

Use os.path.join to concatenate the directory and file name:

for path, subdirs, files in os.walk(root):     for name in files:         print(os.path.join(path, name)) 

Note the usage of path and not root in the concatenation, since using root would be incorrect.

---

In Python 3.4, the pathlib module was added for easier path manipulations. So the equivalent to os.path.join would be:

pathlib.PurePath(path, name) 

The advantage of pathlib is that you can use a variety of useful methods on paths. If you use the concrete Path variant you can also do actual OS calls through them, like changing into a directory, deleting the path, opening the file it points to and much more.

Answer 2

Just in case... Getting all files in the directory and subdirectories matching some pattern (*.py for example):

import os from fnmatch import fnmatch  root = '/some/directory' pattern = "*.py"  for path, subdirs, files in os.walk(root):     for name in files:         if fnmatch(name, pattern):             print os.path.join(path, name)