is there a python library that would make numbers such as this more human readable
$187,280,840,422,780
edited: for example iw ant the output of this to be 187 Trillion not just comma separated. So I want output to be trillions, millions, billions etc
Python supports a "bignum" integer type which can work with arbitrarily large numbers. In Python 2.5+, this type is called long and is separate from the int type, but the interpreter will automatically use whichever is more appropriate.
In conclusion, Python uses Bignum Arithmetic to represent integers. Compared to other languages like Java and C/C++, Python makes working with integers very simple. While other languages require the programmer to determine the size variable to store a number, Python abstracts this need.
Numerize is that library of python which is used to show large numbers into its readable format. It basically converts numerical format into the compact short format. There is no need to show how many zeroes are behind the number.
Type int(x) to convert x to a plain integer. Type long(x) to convert x to a long integer.
As I understand it, you only want the 'most significant' part. To do so, use floor(log10(abs(n)))
to get number of digits and then go from there. Something like this, maybe:
import math millnames = ['',' Thousand',' Million',' Billion',' Trillion'] def millify(n): n = float(n) millidx = max(0,min(len(millnames)-1, int(math.floor(0 if n == 0 else math.log10(abs(n))/3)))) return '{:.0f}{}'.format(n / 10**(3 * millidx), millnames[millidx])
Running the above function for a bunch of different numbers:
for n in (1.23456789 * 10**r for r in range(-2, 19, 1)): print('%20.1f: %20s' % (n,millify(n))) 0.0: 0 0.1: 0 1.2: 1 12.3: 12 123.5: 123 1234.6: 1 Thousand 12345.7: 12 Thousand 123456.8: 123 Thousand 1234567.9: 1 Million 12345678.9: 12 Million 123456789.0: 123 Million 1234567890.0: 1 Billion 12345678900.0: 12 Billion 123456789000.0: 123 Billion 1234567890000.0: 1 Trillion 12345678900000.0: 12 Trillion 123456789000000.0: 123 Trillion 1234567890000000.0: 1235 Trillion 12345678899999998.0: 12346 Trillion 123456788999999984.0: 123457 Trillion 1234567890000000000.0: 1234568 Trillion
With Python2.7+ or v3 you just use the "," option in your string formatting - see PEP 378: Format Specifier for Thousands Separator for more info:
>>> "{:,}".format(100000000) '100,000,000'
With Python3.6+ you can also use the "_" format - see PEP 515 for details:
>>> "{:_}".format(100000000) '100_000_000'
or you can use a similar syntax with f-strings:
>>> number = 100000000 >>>f"{number:,}" '100,000,000'
So I don't have to squint while reading big numbers, I have the 2.7 version of the code wrapped up in a shell function:
human_readable_numbers () { python2.7 -c "print('{:,}').format($1)" }
Lastly, if for some reason you must work with code from Python versions 2.6 or earlier, you can solve the problem using the locale
standard library module:
import locale locale.setlocale(locale.LC_ALL, 'en_US') locale.format('%d', 2**32, grouping=True) # returns '4,294,967,296'
That number seems pretty human-readable to me. An unfriendly number would be 187289840422780.00. To add commas, you could create your own function or search for one (I found this):
import re
def comma_me(amount):
orig = amount
new = re.sub("^(-?\d+)(\d{3})", '\g<1>,\g<2>', amount)
if orig == new:
return new
else:
return comma_me(new)
f = 12345678
print comma_me(`f`)
Output: 12,345,678
If you want to round a number to make it more readable, there is a python function for that: round()
.
You could move even further away from the actual data and say "A very high amount" or "Above 100 trillion" using a function that would return a different value based on your programmed benchmarks.
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