First, open a file in binary write mode and then specify the contents to write in the form of bytes. Next, use the write function to write the byte contents to a binary file.
To write to a binary fileUse the WriteAllBytes method, supplying the file path and name and the bytes to be written. This example appends the data array CustomerData to the file named CollectedData. dat .
Step 1: Searching for the word in the binary file. Step 2: While searching in the file, the variable “pos” stores the position of file pointer record then traverse(continue) reading of the record. Step 3: If the word to be searched exists then place the write pointer (to ending of the previous record) i.e. at pos.
"Option C: dump()". The dump() is used for writing data to a binary file.
This is exactly what bytearray
is for:
newFileByteArray = bytearray(newFileBytes)
newFile.write(newFileByteArray)
If you're using Python 3.x, you can use bytes
instead (and probably ought to, as it signals your intention better). But in Python 2.x, that won't work, because bytes
is just an alias for str
. As usual, showing with the interactive interpreter is easier than explaining with text, so let me just do that.
Python 3.x:
>>> bytearray(newFileBytes)
bytearray(b'{\x03\xff\x00d')
>>> bytes(newFileBytes)
b'{\x03\xff\x00d'
Python 2.x:
>>> bytearray(newFileBytes)
bytearray(b'{\x03\xff\x00d')
>>> bytes(newFileBytes)
'[123, 3, 255, 0, 100]'
Use struct.pack
to convert the integer values into binary bytes, then write the bytes. E.g.
newFile.write(struct.pack('5B', *newFileBytes))
However I would never give a binary file a .txt
extension.
The benefit of this method is that it works for other types as well, for example if any of the values were greater than 255 you could use '5i'
for the format instead to get full 32-bit integers.
As of Python 3.2+, you can also accomplish this using the to_bytes
native int method:
newFileBytes = [123, 3, 255, 0, 100]
# make file
newFile = open("filename.txt", "wb")
# write to file
for byte in newFileBytes:
newFile.write(byte.to_bytes(1, byteorder='big'))
I.e., each single call to to_bytes
in this case creates a string of length 1, with its characters arranged in big-endian order (which is trivial for length-1 strings), which represents the integer value byte
. You can also shorten the last two lines into a single one:
newFile.write(''.join([byte.to_bytes(1, byteorder='big') for byte in newFileBytes]))
To convert from integers < 256 to binary, use the chr
function. So you're looking at doing the following.
newFileBytes=[123,3,255,0,100]
newfile=open(path,'wb')
newfile.write((''.join(chr(i) for i in newFileBytes)).encode('charmap'))
You can use the following code example using Python 3 syntax:
from struct import pack
with open("foo.bin", "wb") as file:
file.write(pack("<IIIII", *bytearray([120, 3, 255, 0, 100])))
Here is shell one-liner:
python -c $'from struct import pack\nwith open("foo.bin", "wb") as file: file.write(pack("<IIIII", *bytearray([120, 3, 255, 0, 100])))'
Use pickle, like this: import pickle
Your code would look like this:
import pickle
mybytes = [120, 3, 255, 0, 100]
with open("bytesfile", "wb") as mypicklefile:
pickle.dump(mybytes, mypicklefile)
To read the data back, use the pickle.load method
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