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This is very simple.I am sure I am missing something silly.
fp = open(r'D:\UserManagement\invitationTemplate.html', 'rb')
html = Template(fp.read())
fp.close()
html.safe_substitute(toFirstName='jibin',fromFirstName='Vishnu')
print html
When i run this code in intepreter directly,I get the proper output.
But when I run it from a file.I get <string.Template object at 0x012D33B0>.How do I convert from string.Template object to string.I have tried str(html).By the bye wasn't print statement supposed to do that(string conversion) ?
733
The Python string Template is created by passing the template string to its constructor. It supports $-based substitutions. This class has 2 key methods: substitute(mapping, **kwds): This method performs substitutions using a dictionary with a process similar to key-based mapping objects.
It uses Template class from string module. It has a syntax somewhat similar to . format() when done with keywords, but instead of curly braces to define the placeholder, it utilises a dollar sign ($). ${} is also valid and should be in place when a valid string comes after the placeholder.
The substitute() Method This method replaces the placeholders in a template string using keyword arguments or using a mapping containing identifier-value pairs.
safe_substitute returns, as a string, the template with the substitutions made. This way, you can reuse the same template for multiple substitutions. So your code has to be
print html.safe_substitute(toFirstName='jibin',fromFirstName='Vishnu')
According to the docs you should take the return Value of safe_substitute
fp = open(r'D:\UserManagement\invitationTemplate.html', 'rb')
html = Template(fp.read())
fp.close()
result = html.safe_substitute(toFirstName='jibin',fromFirstName='Vishnu')
print result
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