I have a message which reads as 14 09 00 79 3d 00 23 27
. I can extract each byte from this message by calling message[4]
, which will give me 3d
for example. How do I extract the individual 8 bits from this byte? For example, how would I get bits 24-27 as as single message? How about just bit 28?
*/ Step 1 : first convert the number into its binary form using bin(). Step 2 : remove the first two character. Step 3 : then extracting k bits from starting position pos from right.so, the ending index of the extracting substring is e=len(bi)-pos and starting index=e-k+1 Step 4 : extract k bit sub-string.
For accessing a specific bit, you can use Shift Operators . If it is always a 1 that you are going to reset, then you could use an & operation. But, if it can also take 0 value, then & operation will fail as 0 & 1 = 0 . You could use | (OR) during that time.
To find necessary bits to represent a number – we use "bit_length()" method of "int" class, it is called with an integer object and returns the total number of bits to require to store/represent an integer number in binary. Note: If the value is 0, bit_length() method returns 0.
To answer the second part of your question, you can get specific bit values using bitwise operations
# getting your message as int
i = int("140900793d002327", 16)
# getting bit at position 28 (counting from 0 from right)
(i >> 28) & 1
# getting bits at position 24-27
bin((i >> 24) & 0b111)
The easiest way to do this is to use the & operator. Convert your message to an int using int(str_msg, 16)
. convert int to binary string using bin(myint)
To get bits 4-6 (from left) in a byte:
>> msg = int("10110111", 2) # or 0b10110111
>> extractor = int("00011100", 2) # or 0b10110111
>> result = msg & extractor
>> print bin(result)
00010100
If you want, you can bit shift result using result >> 2
. Obviously you will want to make this more dynamic but this is a dumbed down example.
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