Python Glob.glob: a wildcard for the number of directories between the root and the destination

Question

Okay I'm having trouble not only with the problem itself but even with trying to explain my question. I have a directory tree consisting of about 7 iterations, so: rootdir/a/b/c/d/e/f/destinationdir

The thing is some may have 5 subdirectory levels and some may have as many as ten, such as:

rootdir/a/b/c/d/destinationdir

or:

rootdir/a/b/c/d/e/f/g/h/destinationdir

The only thing they have in common is that the destination directory is always named the same thing. The way I'm using the glob function is as follows:

for path in glob.glob('/rootdir/*/*/*/*/*/*/destinationdir'):
--- os.system('cd {0}; do whatever'.format(path))

However, this only works for the directories with that precise number of intermediate subdirectories. Is there any way for me not to have to specify that number of subdirectories(asterices); in other words having the function arrive at the destinationdir no matter what the number of intermediate subdirectories is, and allowing me to iterate through them. Thanks a lot!

Answer 1

I think this could be done more easily with os.walk:

def find_files(root,filename):
    for directory,subdirs,files in os.walk(root):
        if filename in files:
            yield os.join(root,directory,filename)

Of course, this doesn't allow you to have a glob expression in the filename portion, but you could check that stuff using regex or fnmatch.

EDIT

Or to find a directory:

def find_files(root,d):
    for directory,subdirs,files in os.walk(root):
        if d in subdirs:
            yield os.join(root,directory,d)