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Given a long string such as:
"fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"
or
"0.53489082304804918409853091868095809846545421135498495431231"
How do I find the value of the nth character in that string? I could solve this if I could convert it into a list (where each digit gets it's own index) but since the numbers aren't separated by commas I don't know how to do this either.
AFAIK there is no command like string.index(10) which would return the 11th character in.
587
To find the ASCII value of a character, we can use the ord() function, which is a built-in function in Python that accepts a char (string of length 1) as argument and returns the unicode code point for that character.
You can extract a substring in the range start <= x < stop with [start:step] . If start is omitted, the range is from the beginning, and if end is omitted, the range is to the end. You can also use negative values. If start > end , no error is raised and an empty character '' is extracted.
The strchr() function finds the first occurrence of a character in a string. The character c can be the null character (\0); the ending null character of string is included in the search. The strchr() function operates on null-ended strings.
strings are like lists. so you can access them the same way,
>>> a = "fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"
>>> print a[10]
k
To get the corresponding character in the nth value, just use this function:
def getchar(string, n):
return str(string)[n - 1]
Example usage:
>>> getchar('Hello World', 5)
'o'
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