Python: Expected an indented block [duplicate]

Question

I thought everything was properly indented here but I am getting an IndentationError: expected an indented block at the else: statement. Am I making an obvious mistake here?

def anti_vowel(text):
    new_string = ""
    vowels = "aeiou"
    for letter in text:
       for vowel in vowels:
           if (lower(letter) == vowel):
               #do nothing
           else:
               #append letter to the new string
               new_string += letter
    return new_string

Answer 1

Do nothing translates to using the pass keyword to fill an otherwise empty block (which is not allowed). See the official documentation for more information.

def anti_vowel(text):
    new_string = ""
    vowels = "aeiou"
    for letter in text:
       for vowel in vowels:
           if (lower(letter) == vowel):
               #do nothing
               pass
           else:
               #append letter to the new string
               new_string += letter
    return new_string

Answer 2

You need to put something inside the if block. If you don't want to do anything, put pass.

Alternatively, just reverse your condition so you only have one block:

if lower(letter) != vowel:
    new_string += letter

Incidentally, I don't think your code will do what you intend it to do, but that's an issue for another question.