Python decorator makes function forget that it belongs to a class

Question

I am trying to write a decorator to do logging:

def logger(myFunc):     def new(*args, **keyargs):         print 'Entering %s.%s' % (myFunc.im_class.__name__, myFunc.__name__)         return myFunc(*args, **keyargs)      return new  class C(object):     @logger     def f():         pass  C().f() 

I would like this to print:

Entering C.f 

but instead I get this error message:

AttributeError: 'function' object has no attribute 'im_class' 

Presumably this is something to do with the scope of 'myFunc' inside 'logger', but I've no idea what.

Answer 1

Claudiu's answer is correct, but you can also cheat by getting the class name off of the self argument. This will give misleading log statements in cases of inheritance, but will tell you the class of the object whose method is being called. For example:

from functools import wraps  # use this to preserve function signatures and docstrings def logger(func):     @wraps(func)     def with_logging(*args, **kwargs):         print "Entering %s.%s" % (args[0].__class__.__name__, func.__name__)         return func(*args, **kwargs)     return with_logging  class C(object):     @logger     def f(self):         pass  C().f() 

As I said, this won't work properly in cases where you've inherited a function from a parent class; in this case you might say

class B(C):     pass  b = B() b.f() 

and get the message Entering B.f where you actually want to get the message Entering C.f since that's the correct class. On the other hand, this might be acceptable, in which case I'd recommend this approach over Claudiu's suggestion.