I have a Python module, wrapper.py
, that wraps a C DLL. The DLL lies in the same folder as the module. Therefore, I use the following code to load it:
myDll = ctypes.CDLL("MyCDLL.dll")
This works if I execute wrapper.py
from its own folder. If, however, I run it from elsewhere, it fails. That's because ctypes computes the path relative to the current working directory.
My question is, is there a way by which I can specify the DLL's path relative to the wrapper instead of the current working directory? That will enable me to ship the two together and allow the user to run/import the wrapper from anywhere.
You can use os.path.dirname(__file__)
to get the directory where the Python source file is located.
Expanding on Matthew's answer:
import os.path dll_name = "MyCDLL.dll" dllabspath = os.path.dirname(os.path.abspath(__file__)) + os.path.sep + dll_name myDll = ctypes.CDLL(dllabspath)
This will only work from a script, not the console nor from py2exe
.
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