I would like to convert string date format to timestamp with microseconds I try the following but not giving expected result:
"""input string date -> 2014-08-01 04:41:52,117
expected result -> 1410748201.117"""
import time
import datetime
myDate = "2014-08-01 04:41:52,117"
timestamp = time.mktime(datetime.datetime.strptime(myDate, "%Y-%m-%d %H:%M:%S,%f").timetuple())
print timestamp
> 1410748201.0
Where did the milliseconds go?
Import the datetime library. Use the datetime. datetime class to handle date and time combinations. Use the strptime method to convert a string datetime to a object datetime.
You can get the current time in milliseconds in Python using the time module. You can get the time in seconds using the time. time function (as a floating point value). To convert it to milliseconds, you need to multiply it by 1000 and round up.
A simple solution is to get the timedelta object by finding the difference of the given datetime with Epoch time, i.e., midnight 1 January 1970. To obtain time in milliseconds, you can use the timedelta. total_seconds() * 1000 .
In Python 3.4 and later you can use
timestamp = datetime.datetime.strptime(myDate, "%Y-%m-%d %H:%M:%S,%f").timestamp()
This doesn't require importing the time
module. It also uses less steps so it should be faster. For older versions of python the other provided answers are probably your best option.
However, the resulting timestamp will interpret myDate in local time, rather than UTC, which may cause issues if myDate was given in UTC
There is no slot for the microseconds component in a time tuple:
>>> import time
>>> import datetime
>>> myDate = "2014-08-01 04:41:52,117"
>>> datetime.datetime.strptime(myDate, "%Y-%m-%d %H:%M:%S,%f").timetuple()
time.struct_time(tm_year=2014, tm_mon=8, tm_mday=1, tm_hour=4, tm_min=41, tm_sec=52, tm_wday=4, tm_yday=213, tm_isdst=-1)
You'll have to add those manually:
>>> dt = datetime.datetime.strptime(myDate, "%Y-%m-%d %H:%M:%S,%f")
>>> time.mktime(dt.timetuple()) + (dt.microsecond / 1000000.0)
1406864512.117
The other method you could follow is to produce a timedelta()
object relative to the epoch, then get the timestamp with the timedelta.total_seconds()
method:
epoch = datetime.datetime.fromtimestamp(0)
(dt - epoch).total_seconds()
The use of a local time epoch is quite deliberate since you have a naive (not timezone-aware) datetime value. This method can be inaccurate based on the history of your local timezone however, see J.F. Sebastian's comment. You'd have to convert the naive datetime value to a timezone-aware datetime value first using your local timezone before subtracting a timezone-aware epoch.
As such, it is easier to stick to the timetuple()
+ microseconds approach.
Demo:
>>> dt = datetime.datetime.strptime(myDate, "%Y-%m-%d %H:%M:%S,%f")
>>> epoch = datetime.datetime.fromtimestamp(0)
>>> (dt - epoch).total_seconds()
1406864512.117
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