python check if a method is called without mocking it away

Question

class A():     def tmp(self):         print("hi")  def b(a):     a.tmp() 

To check if tmp method is called in b, the recommended way is

a = A() a.tmp = MagicMock() b(a) a.tmp.assert_called() 

But tmp here is being mocked away and is not resulting in a "hi" getting printed.

I would want my unit test to check if method tmp is called without mocking it away.

Is this possible?

I know this is not a standard thing to expect when writing unitests. But my use case (which is bit tricky) requires this.

Answer 1

You can set the Mock.side_effect to be the original method.

from unittest.mock import MagicMock  class A():     def tmp(self):         print("hi")  def b(a):     a.tmp()  a = A() a.tmp = MagicMock(side_effect=a.tmp) b(a) a.tmp.assert_called() 

When side_effect is a function (or a bound method in this case, which is a kind of function), calling the Mock will also call the side_effect with the same arguments.

The Mock() call will return whatever the side_effect returns, unless it returns the unnittest.mock.DEFAULT singleton. Then it will return Mock.return_value instead.