Python big file parsing with re

Question

How to parse a large file with regular expressions (using the re module), without loading the whole file in string (or memory)? Memory mapped files don't help because their content can't be converted to some kind of lazy string. The re module only supports string as content argument.

#include <boost/format.hpp>
#include <boost/iostreams/device/mapped_file.hpp>
#include <boost/regex.hpp>
#include <iostream>

int main(int argc, char* argv[])
{
    boost::iostreams::mapped_file fl("BigFile.log");
    //boost::regex expr("\\w+>Time Elapsed .*?$", boost::regex::perl);
    boost::regex expr("something usefull");
    boost::match_flag_type flags = boost::match_default;
    boost::iostreams::mapped_file::iterator start, end;
    start = fl.begin();
    end = fl.end();
    boost::match_results<boost::iostreams::mapped_file::iterator> what;
    while(boost::regex_search(start, end, what, expr))
    {
        std::cout<<what[0].str()<<std::endl;
        start = what[0].second;
    }
    return 0;
}

To demonstrate my requirements. I wrote a short sample using C++(and boost) the same I want to have in Python.

Answer 1

Everything now works ok(Python 3.2.3 has some differences with Python 2.7 in interface). Search patter should be just prefixed with b" to have a working solution(in Python 3.2.3).

import re
import mmap
import pprint

def ParseFile(fileName):
    f = open(fileName, "r")
    print("File opened succesfully")
    m = mmap.mmap(f.fileno(), 0, access = mmap.ACCESS_READ)
    print("File mapped succesfully")
    items = re.finditer(b"\\w+>Time Elapsed .*?\n", m)
    for item in items:
        pprint.pprint(item.group(0))

if __name__ == "__main__":
    ParseFile("testre")