How can I encode an integer with base 36 in Python and then decode it again?
Have you tried Wikipedia's sample code?
def base36encode(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
"""Converts an integer to a base36 string."""
if not isinstance(number, (int, long)):
raise TypeError('number must be an integer')
base36 = ''
sign = ''
if number < 0:
sign = '-'
number = -number
if 0 <= number < len(alphabet):
return sign + alphabet[number]
while number != 0:
number, i = divmod(number, len(alphabet))
base36 = alphabet[i] + base36
return sign + base36
def base36decode(number):
return int(number, 36)
print base36encode(1412823931503067241)
print base36decode('AQF8AA0006EH')
I wish I had read this before. Here is the answer:
def base36encode(number):
if not isinstance(number, (int, long)):
raise TypeError('number must be an integer')
is_negative = number < 0
number = abs(number)
alphabet, base36 = ['0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ', '']
while number:
number, i = divmod(number, 36)
base36 = alphabet[i] + base36
if is_negative:
base36 = '-' + base36
return base36 or alphabet[0]
def base36decode(number):
return int(number, 36)
print(base36encode(1412823931503067241))
print(base36decode('AQF8AA0006EH'))
assert(base36decode(base36encode(-9223372036721928027)) == -9223372036721928027)
from numpy import base_repr
num = base_repr(num, 36)
num = int(num, 36)
Here is information about numpy.base_repr
.
You can use numpy's base_repr(...)
for this.
import numpy as np
num = 2017
num = np.base_repr(num, 36)
print(num) # 1K1
num = int(num, 36)
print(num) # 2017
Here is some information about numpy, int(x, base=10)
, and np.base_repr(number, base=2, padding=0)
.
(This answer was originally submitted as an edit to @christopher-beland's answer, but was rejected in favor of its own answer.)
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