Python: Assigning "through" an iterator

Question

I have an iterator over a mutable sequence, e.g.

foo = [1, 2, 3, 4, 5]
for bar in foo:

Is there a way to write to the elements in foo by using the reference which is contained in the iterator? The naive assignment:

   bar = 42

does not work of course. Is it possible to use the "behind the curtain" reference to the sequence element which is in the iterator ?

PS: The simple solution with using an index

for i in range(len(a)):
   a[i] = 42

will not work for my case, as I can't expose the container name.

Answer 1

Use enumerate() to generate indices for you in the loop:

for i, bar in enumerate(foo):
    foo[i] = bar + 42

Answer 2

From my understanding, your use case is something like this:

class Z:
    def __init__(self):
        self.a, self.b, self.c = 1, 2, 3

    def it(self):
        for x in self.a, self.b, self.c:
            yield x

z = Z()
for x in z.it():
    if x == 1:
       x = 42 # z.a should be 42? - doesn't work!

This isn't possible in python - there's no "pointer" or "reference" data type. You can work around this by yielding a setter function instead of (or along with) the value:

class Z:
    def __init__(self):
        self.a, self.b, self.c = 1,2,3

    def it(self):
        for x in 'abc':
            yield getattr(self, x), lambda y: setattr(self, x, y)

z = Z()
for x, setter in z.it():
    if x == 1:
       setter(42) # works!