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I have the following code :
PropertyInfo[] originalProperties = myType.GetProperties(); I want to exclude from originalProperties all the indexers (myVar["key"] appears as property named "Item").
What is the proper way ?
Exclude all properties where propInfo.Name == "Item" is not an option.
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Properties are identified by the names. While indexers are identified by the signatures. 3. Properties can be declared as a static or an instance member. Indexers are always declared as instance member, never as static member.
< Previous Next > The PropertyInfo class discovers the attributes of a property and provides access to property metadata. The PropertyInfo class is very similar to the FieldInfo class and also contains the ability to set the value of the property on an instance.
Indexers allow instances of a class or struct to be indexed just like arrays. The indexed value can be set or retrieved without explicitly specifying a type or instance member. Indexers resemble properties except that their accessors take parameters.
Call PropertyInfo.GetIndexParameters - if the returned array is empty, it's not an indexer.
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Another option is to use:
myType.GetProperties().Except(myType.GetDefaultMembers().OfType<PropertyInfo>()); GetDefaultMembers will return all the compiler generated indexers in C#. This has the advantage of not needing to reflect on each individual property in order to find out which ones are indexers.
This might not be a general solution for all allowed .NET framework languages, but I am currently not aware of any counter-examples.
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