Printing with sed or awk a line following a matching pattern

Question

Question: I'd like to print a single line directly following a line that contains a matching pattern.

My version of sed will not take the following syntax (it bombs out on +1p) which would seem like a simple solution:

sed -n '/ABC/,+1p' infile 

I assume awk would be better to do multiline processing, but I am not sure how to do it.

Answer 1

Never use the word "pattern" as is it highly ambiguous. Always use "string" or "regexp" (or in shell "globbing pattern"), whichever it is you really mean.

The specific answer you want is:

awk 'f{print;f=0} /regexp/{f=1}' file 

or specializing the more general solution of the Nth record after a regexp (idiom "c" below):

awk 'c&&!--c; /regexp/{c=1}' file 

The following idioms describe how to select a range of records given a specific regexp to match:

a) Print all records from some regexp:

awk '/regexp/{f=1}f' file 

b) Print all records after some regexp:

awk 'f;/regexp/{f=1}' file 

c) Print the Nth record after some regexp:

awk 'c&&!--c;/regexp/{c=N}' file 

d) Print every record except the Nth record after some regexp:

awk 'c&&!--c{next}/regexp/{c=N}1' file 

e) Print the N records after some regexp:

awk 'c&&c--;/regexp/{c=N}' file 

f) Print every record except the N records after some regexp:

awk 'c&&c--{next}/regexp/{c=N}1' file 

g) Print the N records from some regexp:

awk '/regexp/{c=N}c&&c--' file 

I changed the variable name from "f" for "found" to "c" for "count" where appropriate as that's more expressive of what the variable actually IS.

f is short for found. Its a boolean flag that I'm setting to 1 (true) when I find a string matching the regular expression regexp in the input (/regexp/{f=1}). The other place you see f on it's own in each script it's being tested as a condition and when true causes awk to execute its default action of printing the current record. So input records only get output after we see regexp and set f to 1/true.

c && c-- { foo } means "if c is non-zero then decrement it and if it's still non-zero then execute foo" so if c starts at 3 then it'll be decremented to 2 and then foo executed, and on the next input line c is now 2 so it'll be decremented to 1 and then foo executed again, and on the next input line c is now 1 so it'll be decremented to 0 but this time foo will not be executed because 0 is a false condition. We do c && c-- instead of just testing for c-- > 0 so we can't run into a case with a huge input file where c hits zero and continues getting decremented so often it wraps around and becomes positive again.

Answer 2

It's the line after that match that you're interesting in, right? In sed, that could be accomplished like so:

sed -n '/ABC/{n;p}' infile 

Alternatively, grep's A option might be what you're looking for.

-A NUM, Print NUM lines of trailing context after matching lines. 

For example, given the following input file:

foo bar baz bash bongo 

You could use the following:

$ grep -A 1 "bar" file bar baz $ sed -n '/bar/{n;p}' file baz 

Hope that helps.