Printing JSON object using PHP

Question

I have a JSON file and I would like to print that object in JSON:

JSON

[{"text": "Aachen, Germany - Aachen/Merzbruck (AAH)"}, {"text": "Aachen, Germany - Railway (ZIU)"}, {"text": "Aalborg, Denmark - Aalborg (AAL)"}, {"text": "Aalesund, Norway - Vigra (AES)"}, {"text": "Aarhus, Denmark - Aarhus Airport (AAR)"}, {"text": "Aarhus Limo, Denmark - Aarhus Limo (ZBU)"}, {"text": "Aasiaat, Greenland - Aasiaat (JEG)"}, {"text": "Abadan, Iran - Abadan (ABD)"}]

I have tried with following method,

<?php   
  $jsonurl='http://website.com/international.json'; 
  $json = file_get_contents($jsonurl,0,null,null);  
  $json_output = json_decode($json);        
  foreach ($json_output as $trend)  
  {         
   echo "{$trend->text}\n";     
  } 
?>

but it didn't work:

Fatal error: Call to undefined function var_dup() in /home/dddd.com/public_html/exp.php on line 5

Can anyone help me understand what I'm doing wrong?

Answer 1

<?php   

  $jsonurl='http://website.com/international.json'; 
  $json = file_get_contents($jsonurl,0,null,null);  
  $json_output = json_decode($json, JSON_PRETTY_PRINT); 
  echo $json_output;
?>

by using JSON_PRETTY_PRINT u transform your json to pretty formatting, using json_decode($json, true) doesn't reformat your json to PRETTY formatted output, also you don't have to run loop over all keys to export same JSON object again, you could use those constants also which could clean up your json object before exporting it.

json_encode($json, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES)