printf formatting (%d versus %u)

Question

You can find a list of formatting escapes on this page.

%d is a signed integer, while %u is an unsigned integer. Pointers (when treated as numbers) are usually non-negative.

If you actually want to display a pointer, use the %p format specifier.

%u prints unsigned integer

%d prints signed integer

to get a pointer address use %p

Other List of Formatting Escapes:

Here are the full list of formatting escapes. I am just giving a screen shot from this page

If I understand your question correctly, you need %p to show the address that a pointer is using, for example:

int main() {
    int a = 5;
    int *p = &a;
    printf("%d, %u, %p", p, p, p);

    return 0;
}

will output something like:

-1083791044, 3211176252, 0xbf66a93c

%u is used for unsigned integer. Since the memory address given by the signed integer address operator %d is -12, to get this value in unsigned integer, Compiler returns the unsigned integer value for this address.