Print current call stack from a method in Python code

Question

In Python, how can I print the current call stack from within a method (for debugging purposes).

Answer 1

Here's an example of getting the stack via the traceback module, and printing it:

import traceback  def f():     g()  def g():     for line in traceback.format_stack():         print(line.strip())  f()  # Prints: # File "so-stack.py", line 10, in <module> #     f() # File "so-stack.py", line 4, in f #     g() # File "so-stack.py", line 7, in g #     for line in traceback.format_stack(): 

If you really only want to print the stack to stderr, you can use:

traceback.print_stack() 

Or to print to stdout (useful if want to keep redirected output together), use:

traceback.print_stack(file=sys.stdout) 

But getting it via traceback.format_stack() lets you do whatever you like with it.