Print char pointer char array with printf?

Question

I'm trying to print the whole word instead of just the first letter. I could do it with a loop but I figured there was a better way. I was searching around and saw answers that they changed %S to %c but I'm already using %c since it's a character array.

char* words[] = {"my", "word", "list"};
printf("The word: %c",*words[2]);

Results:
The word: l

Answer 1

The issue is that you dereferenced twice. The [2] in *words[2] dereferences from words[] to "list" then the * dereferences a second time from "list" to 'l' Remove the * and voila.

char* words[] = {"my", "word", "list"};
printf("The word: %s", words[2]);

Answer 2

You need to use %s, a format used specifically for null-terminated arrays of characters (i.e. C strings). You do not dereference the array's element when you pass it to printf, like this:

printf("The word: %s\n", words[2]);