Prepare for Segue in Swift

Question

I'm facing the error message:

"UIStoryboardSegue does not have a member named 'identifier'" 

Here's the code causing the error

if (segue.identifier == "Load View") {     // pass data to next view } 

On Obj-C it's fine using like this:

if ([segue.identifier isEqualToString:@"Load View"]) {    // pass data to next view } 

What am I doing wrong?

Answer 1

This seems to be due to a problem in the UITableViewController subclass template. It comes with a version of the prepareForSegue method that would require you to unwrap the segue.

Replace your current prepareForSegue function with:

override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {     if (segue.identifier == "Load View") {         // pass data to next view     } } 

This version implicitly unwraps the parameters, so you should be fine.

Answer 2

Swift 4, Swift 3

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {     if segue.identifier == "MySegueId" {         if let nextViewController = segue.destination as? NextViewController {                 nextViewController.valueOfxyz = "XYZ" //Or pass any values                 nextViewController.valueOf123 = 123         }     } }