Menu
I am using this: if(!preg_match('/^+[0-9]$/', '+1234567'))
and am getting:
Warning: preg_match() [function.preg-match]: Compilation failed: nothing to repeat at offset 1
any ideas why?
update: Now using this: if(!preg_match('/^\+[0-9]$/', '+1234567'))
and am getting no match.
any ideas why?
677
preg_match() in PHP – this function is used to perform pattern matching in PHP on a string. It returns true if a match is found and false if a match is not found. preg_split() in PHP – this function is used to perform a pattern match on a string and then split the results into a numeric array.
preg_match stops looking after the first match. preg_match_all , on the other hand, continues to look until it finishes processing the entire string. Once match is found, it uses the remainder of the string to try and apply another match.
Return Values ¶ preg_match() returns 1 if the pattern matches given subject , 0 if it does not, or false on failure. This function may return Boolean false , but may also return a non-Boolean value which evaluates to false . Please read the section on Booleans for more information.
+ is a special character that indicates 1 or more of the previous character, and by not escaping it you are applying it to the caret. escape it with \ and it will match a literal plus sign.
if(!preg_match('/^\+[0-9]$/', '+1234567'))
EDIT:
The reason why it didn't match is because you specified 1 digit from 0-9 and the end of the string with $. You need to make it a variable amount of digits.
if(!preg_match('/^\+[0-9]+$/', '+1234567')) {
Shorter version:
if(!preg_match('/^\+\d+$/', '+1234567')) {
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
