I know this already been asked, but why doesn't the solution below work? I want to fill value with the last non-null value ordered by idx.
What I see:
idx | coalesce
-----+----------
1 | 2
2 | 4
3 |
4 |
5 | 10
(5 rows)
What I want:
idx | coalesce
-----+----------
1 | 2
2 | 4
3 | 4
4 | 4
5 | 10
(5 rows)
Code:
with base as (
select 1 as idx
, 2 as value
union
select 2 as idx
, 4 as value
union
select 3 as idx
, null as value
union
select 4 as idx
, null as value
union
select 5 as idx
, 10 as value
)
select idx
, coalesce(value
, last_value(value) over (order by case when value is null then -1
else idx
end))
from base
order by idx
What you want is lag(ignore nulls). Here is one way to do what you want, using two window functions. The first defines the grouping for the NULL values and the second assigns the value:
select idx, value, coalesce(value, max(value) over (partition by grp))
from (select b.*, count(value) over (order by idx) as grp
from base b
) b
order by idx;
You can also do this without subqueries by using arrays. Basically, take the last element not counting NULLs:
select idx, value,
(array_remove(array_agg(value) over (order by idx), null))[count(value) over (order by idx)]
from base b
order by idx;
Here is a db<>fiddle.
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