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Use JSON. stringify() to convert the JavaScript object into a JSON string. Send the URL-encoded JSON string to the server as part of the HTTP Request. This can be done using the HEAD, GET, or POST method by assigning the JSON string to a variable.
To send the JSON with payload to the REST API endpoint, you need to enclose the JSON data in the body of the HTTP request and indicate the data type of the request body with the "Content-Type: application/json" request header.
Not sure if you want jQuery.
var form;
form.onsubmit = function (e) {
// stop the regular form submission
e.preventDefault();
// collect the form data while iterating over the inputs
var data = {};
for (var i = 0, ii = form.length; i < ii; ++i) {
var input = form[i];
if (input.name) {
data[input.name] = input.value;
}
}
// construct an HTTP request
var xhr = new XMLHttpRequest();
xhr.open(form.method, form.action, true);
xhr.setRequestHeader('Content-Type', 'application/json; charset=UTF-8');
// send the collected data as JSON
xhr.send(JSON.stringify(data));
xhr.onloadend = function () {
// done
};
};
Here is an example using jQuery...
<head>
<title>Test</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript" src="http://www.json.org/json2.js"></script>
<script type="text/javascript">
$(function() {
var frm = $(document.myform);
var dat = JSON.stringify(frm.serializeArray());
alert("I am about to POST this:\n\n" + dat);
$.post(
frm.attr("action"),
dat,
function(data) {
alert("Response: " + data);
}
);
});
</script>
</head>
The jQuery serializeArray function creates a Javascript object with the form values. Then you can use JSON.stringify to convert that into a string, if needed. And you can remove your body onload, too.
Using the new FormData object (and other ES6 stuff), you can do this to turn your entire form into JSON:
let data = {};
let formdata = new FormData(theform);
for (let tuple of formdata.entries()) data[tuple[0]] = tuple[1];
and then just xhr.send(JSON.stringify(data)); like in Jan's original answer.
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