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Post array of multiple checkbox values

Why is only one value of the "db" checkbox values array being sent to the server side script?

JQUERY:

$(".db").live("change", function() {
    $(this).add($(this).next("label")).add($(this).next().next("br")).remove().insertAfter(".db:last + label + br"); 
    var url = "myurl.php";
    var db = [];
    $.each($('.db:checked'), function() {
        db.push($(this).val()); 
    });
    if(db.length == 0) { 
        db = "none"; 
    }       
    $.post(url, {db: db}, function(response) {
        $("#dbdisplay").html(response); 
    });
    return true;
});

HTML:

<input type="checkbox" name="db[]" class="db" value="track"/><label for="track">track</label></br>
<input type="checkbox" name="db[]" class="db" value="gps"/><label for="gps">gps</label></br>
<input type="checkbox" name="db[]" class="db" value="accounting"/><label for="accounting">accounting</label></br>

Edit: I ended up answering my own question, but does anyone have documentation (or an explanation) of why this is necessary? It was difficult for me to find the exact answer (thus the posthumous post).

like image 669
jjclarkson Avatar asked Oct 12 '09 22:10

jjclarkson


3 Answers

I agree with @jjclarkson. Just to add, instead of pushing your ids to an array, you can use $.map:

$(".db").live("change", function() {
    $(this).add($(this).next("label")).add($(this).next().next("br")).remove().insertAfter(".db:last + label + br"); 
    var url = "myurl.php";

    var db = $('.db:checked').map(function(i,n) {
        return $(n).val();
    }).get(); //get converts it to an array

    if(db.length == 0) { 
        db = "none"; 
    }       
    $.post(url, {'db[]': db}, function(response) {
        $("#dbdisplay").html(response); 
    });
    return true;
});
like image 140
karim79 Avatar answered Nov 02 '22 06:11

karim79


You need to have the square brackets to specify an array [] on the submitted variable name.

{'db[]': db}

$(".db").live("change", function() {
    $(this).add($(this).next("label")).add($(this).next().next("br")).remove().insertAfter(".db:last + label + br"); 
    var url = "myurl.php";
    var db = [];
    $.each($('.db:checked'), function() {
        db.push($(this).val()); 
    });
    if(db.length == 0) { 
        db = "none"; 
    }       
    $.post(url, {'db[]': db}, function(response) {
        $("#dbdisplay").html(response); 
    });
    return true;
});
like image 28
jjclarkson Avatar answered Nov 02 '22 07:11

jjclarkson


var checkeditems = $('input:checkbox[name="review[]"]:checked')
                       .map(function() { return $(this).val() })
                       .get()
                       .join(",");
$.ajax({
    type: "POST",
    url: "/index.php/openItems/",   
    data: "ids=" + checkeditems,                                        
    success: function(msg) { $(".mainContainer").html(msg); }
});
like image 22
Guest Avatar answered Nov 02 '22 06:11

Guest