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I was just curious to know if it is possible to have a pointer referring to #define constant. If yes, how to do it?
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Put another way, the pointer does not hold a value in the traditional sense; instead, it holds the address of another variable. A pointer "points to" that other variable by holding a copy of its address. Because a pointer holds an address rather than a value, it has two parts. The pointer itself holds the address.
As just seen, a variable which stores the address of another variable is called a pointer. Pointers are said to "point to" the variable whose address they store.
Pointer assignment between two pointers makes them point to the same pointee. So the assignment y = x; makes y point to the same pointee as x . Pointer assignment does not touch the pointees. It just changes one pointer to have the same reference as another pointer.
A pointer to a pointer is a form of multiple indirection, or a chain of pointers. Normally, a pointer contains the address of a variable. When we define a pointer to a pointer, the first pointer contains the address of the second pointer, which points to the location that contains the actual value as shown below.
The #define directive is a directive to the preprocessor, meaning that it is invoked by the preprocessor before anything is even compiled.
Therefore, if you type:
#define NUMBER 100
And then later you type:
int x = NUMBER;
What your compiler actually sees is simply:
int x = 100;
It's basically as if you had opened up your source code in a word processor and did a find/replace to replace each occurrence of "NUMBER" with "100". So your compiler has no idea about the existence of NUMBER. Only the pre-compilation preprocessor knows what NUMBER means.
So, if you try to take the address of NUMBER, the compiler will think you are trying to take the address of an integer literal constant, which is not valid.
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