Pointer arithmetic cannot be performed on void pointers because the void type has no size, and thus the pointed address cannot be added to. However, there are non-standard compiler extensions allowing byte arithmetic on void* pointers. Pointers and integer variables are not interchangeable.
The void pointer in C is a pointer that is not associated with any data types. It points to some data location in the storage. This means that it points to the address of variables. It is also called the general purpose pointer. In C, malloc() and calloc() functions return void * or generic pointers.
Advertisements. A pointer in c is an address, which is a numeric value. Therefore, you can perform arithmetic operations on a pointer just as you can on a numeric value. There are four arithmetic operators that can be used on pointers: ++, --, +, and -
You cannot perform arithmetic on a void pointer because pointer arithmetic is defined in terms of the size of the pointed-to object.
Final conclusion: arithmetic on a void*
is illegal in both C and C++.
GCC allows it as an extension, see Arithmetic on void
- and Function-Pointers (note that this section is part of the "C Extensions" chapter of the manual). Clang and ICC likely allow void*
arithmetic for the purposes of compatibility with GCC. Other compilers (such as MSVC) disallow arithmetic on void*
, and GCC disallows it if the -pedantic-errors
flag is specified, or if the -Werror-pointer-arith
flag is specified (this flag is useful if your code base must also compile with MSVC).
Quotes are taken from the n1256 draft.
The standard's description of the addition operation states:
6.5.6-2: For addition, either both operands shall have arithmetic type, or one operand shall be a pointer to an object type and the other shall have integer type.
So, the question here is whether void*
is a pointer to an "object type", or equivalently, whether void
is an "object type". The definition for "object type" is:
6.2.5.1: Types are partitioned into object types (types that fully describe objects) , function types (types that describe functions), and incomplete types (types that describe objects but lack information needed to determine their sizes).
And the standard defines void
as:
6.2.5-19: The
void
type comprises an empty set of values; it is an incomplete type that cannot be completed.
Since void
is an incomplete type, it is not an object type. Therefore it is not a valid operand to an addition operation.
Therefore you cannot perform pointer arithmetic on a void
pointer.
Originally, it was thought that void*
arithmetic was permitted, because of these sections of the C standard:
6.2.5-27: A pointer to void shall have the same representation and alignment requirements as a pointer to a character type.
However,
The same representation and alignment requirements are meant to imply interchangeability as arguments to functions, return values from functions, and members of unions.
So this means that printf("%s", x)
has the same meaning whether x
has type char*
or void*
, but it does not mean that you can do arithmetic on a void*
.
Pointer arithmetic is not allowed on void*
pointers.
cast it to a char pointer an increment your pointer forward x bytes ahead.
The C standard does not allow void pointer arithmetic. However, GNU C is allowed by considering the size of void is 1
.
C11 standard §6.2.5
Paragraph - 19
The
void
type comprises an empty set of values; it is an incomplete object type that cannot be completed.
Following program is working fine in GCC compiler.
#include<stdio.h>
int main()
{
int arr[2] = {1, 2};
void *ptr = &arr;
ptr = ptr + sizeof(int);
printf("%d\n", *(int *)ptr);
return 0;
}
May be other compilers generate an error.
You can't do pointer arithmetic on void *
types, for exactly this reason!
You have to cast it to another type of pointer before doing pointer arithmetic.
Void pointers can point to any memory chunk. Hence the compiler does not know how many bytes to increment/decrement when we attempt pointer arithmetic on a void pointer. Therefore void pointers must be first typecast to a known type before they can be involved in any pointer arithmetic.
void *p = malloc(sizeof(char)*10);
p++; //compiler does how many where to pint the pointer after this increment operation
char * c = (char *)p;
c++; // compiler will increment the c by 1, since size of char is 1 byte.
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