I have some code to plot 3D surfaces in Python using matplotlib:
import math
import numpy as np
import matplotlib.pyplot as plt
from pylab import meshgrid,cm,imshow,contour,clabel,colorbar,axis
from mpl_toolkits.mplot3d import Axes3D
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import seaborn as sns
sns.set(style="white")
def surface_map(func, xmin=0, xmax=1, ymin=0, ymax=1, step_size=0.05, maxz=25000):
X, Y = meshgrid(
np.arange(xmin, xmax, step_size),
np.arange(ymin, ymax, step_size))
Z = np.zeros(X.shape)
for i in range(X.shape[0]):
for j in range(X.shape[1]):
Z[i, j] = min(func(X[i, j], Y[i, j]), maxz)
return X, Y, Z
def plot_surface(X, Y, Z, xlabel, ylabel, zlabel, title, point=None, size=25):
fig = plt.figure()
ax = fig.gca(projection='3d')
surf = ax.plot_surface(X, Y, Z,
rstride=1, cstride=1, vmin=0, vmax=20*1000,
cmap=cm.RdBu, linewidth=0, antialiased=True)
ax.zaxis.set_major_locator(LinearLocator(10))
ax.zaxis.set_major_formatter(FormatStrFormatter('%.02f'))
ax.set_xlabel(xlabel)
ax.set_ylabel(ylabel)
ax.set_zlabel(zlabel)
ax.set_title(title)
fig.colorbar(surf, shrink=0.5, aspect=5)
if point:
ax.hold(True)
func, fpr, recall = point
ax.scatter([fpr], [recall], [
func(fpr, recall)
], s=size, c='b', marker='.', zorder=10)
plt.show()
And then I call it like so:
# create mesh
R, FPR, FuncValue = surface_map(my_function, xmin=0, xmax=1, ymin=0, ymax=1, step_size=0.05, maxz=20*1000)
# plot it
plot_surface(R, FPR, FuncValue,
xlabel="Recall",
ylabel="FPR",
zlabel="Function Value",
title="Recall Settings Payout Function",
point=(my_function, 0.5, 0.5))
I'm setting ax.scatter
to use large marker sizes and a high zorder
, but no point gets drawn on the surface when the plot gets rendered.
What am I missing?
The point you are looking for is there, but hidden "inside" the surface. This is a common problem in matplotlib.
I see two options here:
alpha=.8
or similar. plot
instead of scatter
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