I am isung PHPExcel and have a URL in a string. When doing:
$url = 'http://dx.doi.org/10.1016/j.phymed.2005.11.003'
$xls = new PHPExcel();
$xls->setActiveSheetIndex(0);
$xls->getActiveSheet()->setCellValueByColumnAndRow(1,2,$url);
The url is set as simple text.
I also tried:
$xls->getActiveSheet()->getCellByColumnAndRow(1,2)->getHyperlink()->setUrl('"'.$url.'"');
But then, when clicking on the link, it tries to open a local folder.
Any idea how to do that?
Thank you.
EDIT
When I try do do this without quotes:
$xls->getActiveSheet()->getCellByColumnAndRow(1,2)->getHyperlink()->setUrl($url);
Then I am getting the error:
Exception' with message 'Invalid parameters passed.'
My real url is
http://dx.doi.org/10.1016/j.phymed.2005.11.003
I noticed that when setting a slash at the end, the hyperlink works, but the url is then wrong.
I have found the solution, somehow the url I had was not recognized by excel.
$url = str_replace('http://', '', $link);
$xls->getActiveSheet()->getCellByColumnAndRow(1,2)->getHyperlink()->setUrl('http://www.'.$url);
And now it works. Hope this will help.
I am guessing your field value has integer value. If it is so, then you first have to convert the data type of that cell and then set the hyperlink. Below is how I have done this.
//set the value of the cell
$this->phpExcelObj->getActiveSheet()->SetCellValue('A1',$id);
//change the data type of the cell
$this->phpExcelObj->getActiveSheet()->getCell("A1")->setDataType(PHPExcel_Cell_DataType::TYPE_STRING2);
///now set the link
$this->phpExcelObj->getActiveSheet()->getCell("A1")->getHyperlink()->setUrl(strip_tags($link));
Try to write your code as below line:
$objSheet->setCellValue('A1', '=Hyperlink("https://www.someurl.com/","Mi web")');
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