Lets say I have this XML:
<images>
<photo>
<thumbImg>images/thumbs/002.jpg</thumbImg>
<filename>002</filename>
</photo>
<photo>
<thumbImg>images/thumbs/008.jpg</thumbImg>
<filename>008</filename>
</photo>
<photo>
<thumbImg>images/thumbs/003.jpg</thumbImg>
<filename>003</filename>
</photo>
<photo>
<thumbImg>images/thumbs/006.jpg</thumbImg>
<filename>006</filename>
</photo>
<photo>
<thumbImg>images/thumbs/005.jpg</thumbImg>
<filename>005</filename>
</photo>
</images>
And I want to find the element with the filename value of 003 and then find the elements 1 prior and 1 after that element. This is all so I can get the data for a prev/next functionality as well as show the selected image on a page. I was thinking this would do it:
$image_id = "003";
$project = $xml_object->xpath("photo[filename='$image_id']");
But it print_r's an empty array... Is there an easy way with xpath to do this perhaps? I figured that I could do it by just looping through and putting the prev/next elements into a temp array, then once it's found, break the loop and return the temp data, but I thought xpath might be able to do it a little more elegantly.
EDIT: solved - here's the clearer answer for the sibling nodes:
// for the one prior
//photo[filename='$image_id']/preceding-sibling::photo[1]
// for the one after
//photo[filename='$image_id']/following-sibling::photo[1]
Use this:
$project = $xml_object->xpath("//photo[filename='$image_id']");
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