PHP Search Array column for match

Question

I have an array as below, which has multiple columns. I want to search in the first column for a specific value, and have the rows that match returned. Is that possible to do?

For example:

Array (
[0] => Array ( [id] => 1 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5 ) 
[1] => Array ( [id] => 1 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5 ) 
[2] => Array ( [id] => 2 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5 
)

So let's say I want to search the "id" column for "1" and have the results displayed. How can this be done? Thank you so much!

Answer 1

If you are using PHP >= 5.5, then you can use the new array_column(), in conjunction with array_keys() and array_map().

Given your array, $array:

$keys = array_keys(array_column($array, 'id'), 1);
$new_array = array_map(function($k) use ($array){return $array[$k];}, $keys);

See demo

Answer 2

Since you have an nested Array you need two iterations:

$filtered = array();
$rows = Your Array;
foreach($rows as $index => $columns) {
    foreach($columns as $key => $value) {
        if ($key == 'id' && $value == '1') {
            $filtered[] = $columns;
        }
    }
}

This should do the job.

Answer 3

I found a much simpler solution that I think is worthwhile sharing with the world

in_array(1, array_column($yourArray, 'id'));

Tested on PHP >= 5.5