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Redirect Symfony2 LogoutSuccessHandler to original logout target

Tags:

php

symfony

I need to modify my user object on logout. To do this, I have a security.yml that contains the following (amongst other things) -

#...
    logout:
        success_handler: my.logout_success_handler
        target: /
#...

...this defines a logout success handler, which is defined in services.yml like this -

   my.security.logout_success_handler:
       class: My\Security\LogoutSuccessHandler
       arguments: ["@security.context", "@doctrine.orm.default_entity_manager"]

...finally, the business-end of my handler is like this -

// ...
public function onLogoutSuccess(Request $request)
{

    $user = $this->securityContext->getToken()->getUser();

    // ... do stuff with the user object....
    $this->em->flush();

    // now what?

}
// ...

So, where it says "now what?" I understand that I need to return a Response object. Ideally I want that response object to redirect the user to whatever is defined in logout.target in the security.yml.

Is there an easy way I can query that? Or, even better, is there another way of doing this kind of thing that doesn't require me to get involved with the request/response objects at all?

Thanks

like image 744
Jez Avatar asked Feb 17 '14 17:02

Jez


2 Answers

You could define your target as a parameter in your parameters.yml or config.yml:

parameters:
    logout.target: /

And then reference this value in your security.yml:

    logout:
        success_handler: my.logout_success_handler
        target: %logout.target%   

And/or inject it into your logout handler:

    my.security.logout_success_handler:
        class: My\Security\LogoutSuccessHandler
        arguments: ["@security.context", "@doctrine.orm.default_entity_manager", %logout.target%]

And return a RedirectResponse with this value:

// Assign the 3. constructor parameter to the instance variable $logoutTarget

public function onLogoutSuccess(Request $request)
{
    // ...

    return new RedirectResponse($this->logoutTarget);
}
like image 173
Leif Avatar answered Oct 10 '22 07:10

Leif


So, I think I've figured out the right answer -

Rather than implementing LogoutSuccessHandlerInterface and configuring a logout.success_handler, my security.yml now looks like this -

# ...
logout:
    handlers: [my.bundle.security.logout_handler]
# ...

...and I'm implementing Symfony\Component\Security\Http\Logout\LogoutHandlerInterface. Confusing naming, but this seems to be the preferred way of doing post-logout operations without having to get involved with the response object. My implementation looks like this -

namespace My\Bundle\Security;

use Symfony\Component\Security\Http\Logout\LogoutHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Request;
use Doctrine\ORM\EntityManager;

/**
 * Do post logout stuff
 */
class LogoutHandler implements LogoutHandlerInterface
{

    /**
     * @var EntityManager
     */
    protected $em;

    /**
     * Constructor
     * @param EntityManager $em
     */
    public function __construct(EntityManager $em)
    {

        $this->em = $em;
    }

    /**
     * Do post logout stuff
     */
    public function logout(Request $request, Response $response, TokenInterface $authToken)
    {
        $user = $authToken->getUser();

        // do stuff with the user object...
        $this->em->flush();

        return $response;
    }
}

...as you can see, the LogoutHandlerInterface provides a pre-made $response object that I can just return when I'm finished.

like image 42
Jez Avatar answered Oct 10 '22 08:10

Jez