PHP MySQLi INSERT not working, no errors

Question

Different from this question, but similar in that I don't get an error when adding information to my database.

$sql = "INSERT INTO 'nlcc_ver1'.'tUsers' ('userID', 'userName', 'userPassword', 'userHash',
'user_first_name', 'user_last_name', 'user_corps', 'is_admin', 'is_trg', 'is_sup', 'is_co')
VALUES (NULL, '" . $userName . "', '" . $hash . "', '" . $salt . "', '" . $f_name . "', '" .
$l_name . "', '" . $corps . "', '" . $admin . "', '" . $trg . "', '" . $sup . "', '" . $co . "')";
$hostname_Database = "localhost";
$database_Database = "nlcc_ver1";
$username_Database = "root";
$password_Database = "";
$mysqli = new mysqli($hostname_Database, $username_Database, $password_Database, $database_Database); 
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$result = $mysqli_query($mysqli, $sql);
echo "Query run. Inserted UserID " . mysqli_insert_id($mysqli) . "<br />";

Line breaks inserted to avoid sideways scrolling... It says on the web page that mysqli_insert_id($mysqli) is 0, and nothing is added to the table on my database. I do not see an error connecting to the database appearing, and MySQL is running on my server, and phpinfo() shows both the MySQL and MySQLI extension loaded. This is just a development machine, so don't worry about the security (i.e. no password). I have tried googling the problem, but am not finding too much. I don't know about object oriented PHP programming with ->, I am used to using _. Is this method still supported?

Answer 1

You've mixed procedural and object-oriented MySQLi styles. This has led to you trying to use the functions like mysqli_query($mysqli) instead of the member functions like $mysqli->query(). Your $mysqli is an object, not a resource handle.

And, you're not performing any error checking on your query. If you were, you'd see that you have mistakenly used single quotes to delimit table and field names, not backticks.

$sql = "INSERT INTO `nlcc_ver1`.`tUsers`
       (`userID`, `userName`, `userPassword`, `userHash`,
        `user_first_name`, `user_last_name`, `user_corps`,
        `is_admin`, `is_trg`, `is_sup`, `is_co`)
       VALUES (NULL, '" . $userName . "', '" . $hash . "', '" . $salt . "', '" .
               $f_name . "', '" . $l_name . "', '" . $corps . "', '" . $admin .
               "', '" . $trg . "', '" . $sup . "', '" . $co . "')";

$hostname_Database = "localhost";
$database_Database = "nlcc_ver1";
$username_Database = "root";
$password_Database = "";

$mysqli = new mysqli($hostname_Database, $username_Database, $password_Database, $database_Database); 
if (mysqli_connect_errno()) {
   printf("Connect failed: %s\n", mysqli_connect_error());
   exit();
}

$result = $mysqli->query($sql);
if (!$result) {
   printf("%s\n", $mysqli->error);
   exit();
}

echo "Query run. Inserted UserID " . $mysqli->insert_id . "<br />";

I strongly suggest using the manual as your reference. It's quite clear on how to use these functions when you're using either procedural or object-oriented style MySQLi.

Answer 2

$mysqli_query($mysqli, $sql);

should be

mysqli_query($mysqli, $sql);

OR

$mysqli->query($sql);

AND later on

$mysqli->insert_id();

Answer 3

Look at this:

'nlcc_ver1'.'tUsers'

You have to use backticks here as quote character:

`nlcc_ver1`.`tUsers`

But however(assuming that the $ in $mysqli_query is just a typo): You will not get errors for the query , unless you use mysqli_error() right after executing the query.