PHP inhertience method referencing

Question

<?php
class A {
    private function foo() {
        echo "baf!<br/>";
    }
    public function test() {
        $this->foo();

    }
}


class C extends A {
    private function foo() {
        echo "bar!<br/>";
    }

}

$c = new C();
$c->test();  //Prints baf!
?> 

How to make c->test() to print bar! ? I was expecting that foo() will be overridden in C and would print bar! can someone explain it to me?

Answer 1

By making both methods protected you will achieve the desired result; the reason being that within A::test() it can only resolve $this->foo() to A::foo() because of the private visibility. See Visibility.

class A {
    protected function foo() {
        echo "baf!<br/>";
    }
    public function test() {
        $this->foo();

    }
}


class C extends A {
    protected function foo() {
        echo "bar!<br/>";
    }

}

$c = new C();
$c->test();  //Prints bar!