PHP: How to check whether the URL is Youtube's or vimeo's

Question

How can I write a function to check whether the provided URLs is youtube or vimeo?

For instance, I have this two URLs that I store in a database as strings,

http://vimeo.com/24456787

http://www.youtube.com/watch?v=rj18UQjPpGA&feature=player_embedded

If the URL is youtube then I will rewrite the URL to,

http://www.youtube.com/embed/rj18UQjPpGA?rel=0&wmode=transparent

If the URL is vimeo then I will rewrite this URL to,

http://vimeo.com/moogaloop.swf?clip_id=24456787

Thanks.

Answer 1

Use the parse_url function to split the URL up and then just do your normal checks

$url = 'http://www.youtube.com/watch?v=rj18UQjPpGA&feature=player_embedded';
$parsed = parse_url($url);

Will give you this array

array
  'scheme' => string 'http' (length=4)
  'host' => string 'www.youtube.com' (length=15)
  'path' => string '/watch' (length=6)
  'query' => string 'v=rj18UQjPpGA&feature=player_embedded' (length=37)

Answer 2

I recently wrote this function to do exactly this, hopefully it's useful to someone:

    /**
 * [determineVideoUrlType used to determine what kind of url is being submitted here]
 * @param  string $url either a YouTube or Vimeo URL string
 * @return array will return either "youtube","vimeo" or "none" and also the video id from the url
 */

public function determineVideoUrlType($url) {


    $yt_rx = '/^((?:https?:)?\/\/)?((?:www|m)\.)?((?:youtube\.com|youtu.be))(\/(?:[\w\-]+\?v=|embed\/|v\/)?)([\w\-]+)(\S+)?$/';
    $has_match_youtube = preg_match($yt_rx, $url, $yt_matches);


    $vm_rx = '/(https?:\/\/)?(www\.)?(player\.)?vimeo\.com\/([a-z]*\/)*([‌​0-9]{6,11})[?]?.*/';
    $has_match_vimeo = preg_match($vm_rx, $url, $vm_matches);


    //Then we want the video id which is:
    if($has_match_youtube) {
        $video_id = $yt_matches[5]; 
        $type = 'youtube';
    }
    elseif($has_match_vimeo) {
        $video_id = $vm_matches[5];
        $type = 'vimeo';
    }
    else {
        $video_id = 0;
        $type = 'none';
    }


    $data['video_id'] = $video_id;
    $data['video_type'] = $type;

    return $data;

}

Answer 3

As others have noted in the comments, this is a quick and dirty solution that does not handle edge cases well. If the url contains "youtube"(example.com/youtube) it will return a false positive. The parse_url() solution mentioned below is a much more robust solution.

---

Regular expressions work well for this type of thing, but often strpos or substr are faster performance wise. Check out the PHP documentation for preg_match(). Below the examples there is a note for exactly this thing.

Here is prototype code:

function videoType($url) {
    if (strpos($url, 'youtube') > 0) {
        return 'youtube';
    } elseif (strpos($url, 'vimeo') > 0) {
        return 'vimeo';
    } else {
        return 'unknown';
    }
}

Obviously returning a string isn't the best idea, but you get the point. Substitute your own business logic.