PHP: fopen error handling

Question

I do fetch a file with

$fp = fopen('uploads/Team/img/'.$team_id.'.png', "rb"); $str = stream_get_contents($fp); fclose($fp); 

and then the method gives it back as image. But when fopen() fails, because the file did not exists, it throws an error:

[{"message":"Warning: fopen(uploads\/Team\/img\/1.png): failed to open stream: No such file or directory in C:\... 

This is coming back as json, obviously.

The Question is now: How can i catch the error and prevent the method from throwing this error directly to the client?

Answer 1

You should first test the existence of a file by file_exists().

try {   $fileName = 'uploads/Team/img/'.$team_id.'.png';    if ( !file_exists($fileName) ) {     throw new Exception('File not found.');   }    $fp = fopen($fileName, "rb");   if ( !$fp ) {     throw new Exception('File open failed.');   }     $str = stream_get_contents($fp);   fclose($fp);    // send success JSON  } catch ( Exception $e ) {   // send error message if you can }  

or simple solution without exceptions:

$fileName = 'uploads/Team/img/'.$team_id.'.png'; if ( file_exists($fileName) && ($fp = fopen($fileName, "rb"))!==false ) {    $str = stream_get_contents($fp);   fclose($fp);    // send success JSON     } else {   // send error message if you can   }