PHP explode and array index

Question

How can I get the following code to work?

$a = explode('s', $str)[0];

I only see solutions looking like this:

$a = explode('s', $str); $a=$a[0];

Answer 1

As others have said, PHP is unlike JavaScript in that it can't access array elements from function returns. The second method you listed works. You can also grab the first element of the array with the current(), reset(), or array_pop() functions like so:

$a = current( explode( 's', $str ) ); //or $a = reset( explode( 's', $str ) ); //or $a = array_pop ( explode( 's', $str ) ); 

If you would like to remove the slight overhead that explode may cause due to multiple separations, you can set its limit to 2 by passing two after the other arguments. You may also consider using str_pos and strstr instead:

$a = substr( $str, 0, strpos( $str, 's' ) ); 

Any of these choices will work.

EDIT Another way would be to use list() (see PHP doc). With it you can grab any element:

list( $first ) = explode( 's', $str ); //First list( ,$second ) = explode( 's', $str ); //Second list( ,,$third ) = explode( 's', $str ); //Third //etc. 

That not your style? You can always write a small helper function to grab elements from functions that return arrays:

function array_grab( $arr, $key ) { return( $arr[$key] ); }  $part = array_grab( explode( 's', $str ), 0 ); //Usage: 1st element, etc. 

EDIT: PHP 5.4 will support array dereferencing, so you will be able to do:

$first_element = explode(',','A,B,C')[0]; 

Answer 2

You are correct with your second code-block. explode, and other functions can't return a fully formed array for immediate use,and so you have to set a temporary variable. There may be code in the development tree to do that, but the only way to get the elements you need for now, is the temporary variable.