PHP : Error: Wrong parameters for Exception with thrown Array Exception

Question

I'm throwing the exception using the array like so:

$response = array('login_email' => '<div class="warning">Your email and / or password were incorrect</div>');

throw new \Exception($response);

and what I'm catching is:

Error: Wrong parameters for Exception([string $exception [, long $code [, Exception $previous = NULL]]])

Any idea?

Answer 1

Exception() won't take an array. You need to give it a string.

$response = 'Your email and / or password were incorrect.';

throw new \Exception($response);

Read the error:

Exception([string $exception [, long $code [, Exception $previous = NULL]]])

Answer 2

If you want to throw an exception with an array as parameter, you can json_encode your array so it becomes a string.

$response = array('login_email' => 'sometext', 'last_query' => 'sometext');
throw new \Exception(json_encode($response));

Have a look also at the second parameter of json_encode: you can add JSON_PRETTY_PRINT to have you error indented (it's more readable but it takes more space), or you can use a tool like JSON Viewer for Notepad++ to format your json string when looking at it.