Menu
The is a very simple echo statement but I can't solve it?
echo '"What is your name?'";
499
In PHP, people use single quote to define a constant string, like 'a' , 'my name' , 'abc xyz' , while using double quote to define a string contain identifier like "a $b $c $d" . echo "my $a"; This is true for other used of string.
`echo` command prints the value of this variable without any quotation. When the variable is quoted by single quote then the variable name will print as output. If the backslash ( \ ) is used before the single quote then the value of the variable will be printed with single quote.
Single quoted ¶The simplest way to specify a string is to enclose it in single quotes (the character ' ). To specify a literal single quote, escape it with a backslash ( \ ). To specify a literal backslash, double it ( \\ ).
Mismatch of single quotes, use this:
echo '"What is your name?"';
Your first enclosing character was single quote but ending one was double quote causing the problem
74
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
