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PHP Commands Out of Sync error

Tags:

php

mysql

mysqli

I am using two prepared statements in PHP/MySQLi to retrieve data from a mysql database. However, when I run the statements, I get the "Commands out of sync, you can't run the command now" error.

Here is my code:

    $stmt = $mysqli->prepare("SELECT id, username, password, firstname, lastname, salt FROM members WHERE email = ? LIMIT 1";     $stmt->bind_param('s', $loweredEmail);     $stmt->execute();     $stmt->store_result();     $stmt->bind_result($user_id, $username, $db_password, $firstname, $lastname, $salt);     $stmt->fetch();      $stmt->free_result();     $stmt->close();      while($mysqli->more_results()){         $mysqli->next_result();     }      $stmt1 = $mysqli->prepare("SELECT privileges FROM delegations WHERE id = ? LIMIT 1");     //This is where the error is generated     $stmt1->bind_param('s', $user_id);     $stmt1->execute();     $stmt1->store_result();     $stmt1->bind_result($privileges);     $stmt1->fetch(); 

What I've tried:

  • Moving the prepared statements to two separate objects.
  • Using the code:

    while($mysqli->more_results()){     $mysqli->next_result(); } //To make sure that no stray result data is left in buffer between the first //and second statements 
  • Using free_result() and mysqli_stmt->close()

PS: The 'Out of Sync' error comes from the second statement's '$stmt1->error'

like image 357
user191125 Avatar asked Jan 28 '13 02:01

user191125


People also ask

How do you fix Commands out of sync you can't run this command now?

If you get Commands out of sync; you can't run this command now in your client code, you are calling client functions in the wrong order. This can happen, for example, if you are using mysql_use_result() and try to execute a new query before you have called mysql_free_result() .

What is Mysql_store_result?

Procedural style. mysqli_store_result(mysqli $mysql , int $mode = 0): mysqli_result|false. Transfers the result set from the last query on the database connection represented by the mysql parameter to be used with the mysqli_data_seek() function.


1 Answers

In mysqli::query If you use MYSQLI_USE_RESULT all subsequent calls will return error Commands out of sync unless you call mysqli_free_result()

When calling multiple stored procedures, you can run into the following error: "Commands out of sync; you can't run this command now". This can happen even when using the close() function on the result object between calls. To fix the problem, remember to call the next_result() function on the mysqli object after each stored procedure call. See example below:

<?php // New Connection $db = new mysqli('localhost','user','pass','database');  // Check for errors if(mysqli_connect_errno()){  echo mysqli_connect_error(); }  // 1st Query $result = $db->query("call getUsers()"); if($result){      // Cycle through results     while ($row = $result->fetch_object()){         $user_arr[] = $row;     }     // Free result set     $result->close();     $db->next_result(); }  // 2nd Query $result = $db->query("call getGroups()"); if($result){      // Cycle through results     while ($row = $result->fetch_object()){         $group_arr[] = $row;     }      // Free result set      $result->close();      $db->next_result(); } else echo($db->error);  // Close connection $db->close(); ?> 

I hope this will help

like image 72
G. N. Vashishtha Avatar answered Sep 23 '22 15:09

G. N. Vashishtha