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I understand PHP does not have a pure object variable, but I want to check whether a property is in the given object or class.
$ob = (object) array('a' => 1, 'b' => 12);
or
$ob = new stdClass;
$ob->a = 1;
$ob->b = 2;
In JS, I can write this to check if variable a exists in an object:
if ('a' in ob)
In PHP, can anything like this be done?
453
PHP array_key_exists() Function The array_key_exists() function checks an array for a specified key, and returns true if the key exists and false if the key does not exist.
The is_object() function checks whether a variable is an object. This function returns true (1) if the variable is an object, otherwise it returns false/nothing.
The function in_array() returns true if an item exists in an array. You can also use the function array_search() to get the key of a specific item in an array. In PHP 5.5 and later you can use array_column() in conjunction with array_search() .
With the help of property_exists() you can easily remove "Undefined property" notice from your php file.
if (property_exists($ob, 'a'))
NOTE : Mind that isset() will return false if property is null
if (isset($ob->a))
Example 1:
$ob->a = null
var_dump(isset($ob->a)); // false
Example 2:
class Foo
{
public $bar = null;
}
$foo = new Foo();
var_dump(property_exists($foo, 'bar')); // true
var_dump(isset($foo->bar)); // false
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