PHP Array to Json Object

Question

I need to convert a PHP array to JSON but I don't get what I expect. I want it to be an object that I can navigate easily with a numeric index. Here's an example code:

$json = array();
$ip = "192.168.0.1";
$port = "2016";
array_push($json, ["ip" => $ip, "port" => $port]);
$json = json_encode($json, JSON_PRETTY_PRINT);
// ----- json_decode($json)["ip"] should be "192.168.0.1" ----
echo $json;

This is what I get

[  
   [  
      "ip" => "192.168.0.1",
      "port" => "2016"
   ]
]

But I want to get an object instead of array:

{  
   "0": {  
      "ip": "192.168.0.1",
      "port": "2016"
   }
}

Answer 1

You want to json_encode($json, JSON_FORCE_OBJECT).

The JSON_FORCE_OBJECT flag, as the name implies, forces the json output to be an object, even when it otherwise would normally be represented as an array.

You can also eliminate the use of array_push for some slightly cleaner code:

$json[] = ['ip' => $ip, 'port' => $port];

Answer 2

just use only

$response=array();
$response["0"]=array("ip"     => "192.168.0.1",
                     "port"   => "2016");
$json=json_encode($response,JSON_FORCE_OBJECT);

Answer 3

To get array with objects you can create stdClass() instead of array for inner items like below;

<?PHP

    $json = array();
    $itemObject = new stdClass();
    $itemObject->ip = "192.168.0.1";
    $itemObject->port = 2016;

    array_push($json, $itemObject);
    $json = json_encode($json, JSON_PRETTY_PRINT);
    echo $json;

?>

A working example http://ideone.com/1QUOm6

Answer 4

Just in case if you want to access your objectivitized json whole data OR a specific key value:

PHP SIDE

 $json = json_encode($yourdata, JSON_FORCE_OBJECT);

JS SIDE

 var json = <?=$json?>;
 console.log(json);            // {ip:"192.168.0.1", port:"2016"}
 console.log(json['ip']);      // 192.168.0.1
 console.log(json['port']);    // 2016