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I have this php function that has to perform some processing on a given array:
processArray($arrayToProcess) {
$arrayToProcess['helloStackOverflow'] = TRUE;
}
Later, the code invokes the following:
$niceArray = array('key' => 'value');
processArray($niceArray);
The key 'helloStackOverflow' isn't available outside the processArray function. I tried calling the following:
processArray(&$niceArray);
Using "&" helps, however it raises some warning:
Deprecated function: Call-time pass-by-reference has been deprecated; If you would like to pass it by reference, modify the declaration of populateForm_withTextfields()
Tried the & in there, but that just stops the code.
How should I do this?
294
Like normal variables, you can pass an array by reference into a function by taking a reference of the original array, and passing the reference to the function. Here is a PHP script on how to pass array as reference: <?
In C function arguments are always passed by value. In case of an array (variable), while passed as a function argument, it decays to the pointer to the first element of the array. The pointer is then passed-by-value, as usual.
Like all Java objects, arrays are passed by value ... but the value is the reference to the array. Real passing by reference involves passing the address of a variable so that the variable can be updated. This is NOT what happens when you pass an array in Java.
A whole array cannot be passed as an argument to a function in C++. You can, however, pass a pointer to an array without an index by specifying the array's name. In C, when we pass an array to a function say fun(), it is always treated as a pointer by fun().
You have to define the reference in the function, not in the call to the function.
function processArray(&$arrayToProcess) {
processArray(&$arrayToProcess) {
$arrayToProcess['helloStackOverflow'] = TRUE;
}
implements the reference in PHP way.
See http://fi2.php.net/references for useful information about references.
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