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PHP 5.4 code update - Creating default object from empty value warnings in foreach and objects array

I have following code:

foreach($foo as $n=>$ia) {
    foreach($ia as $i=>$v) {
    $bar[$i]->$n = $v; //here I have 'Creating default object...' warning
    }
}

If I add:

$bar[$i] = new stdClass;
$bar[$i]->$n = $v;

to fix it. Then values in objects in array 'bar' not sets. For example, I have array:

 $foo = array(
 "somefield" => array("value1", "value2", "value3"),
 "anotherfield" => array("value1", "value2", "value3")
 );

On output I should get:

$bar[0]->somefield = value1
$bar[1]->anotherfield = value2

But in practice I get:

$bar[0]->somefield = null //(not set)
$bar[1]->anotherfield = null //too

How should I update the code to get it work?

like image 530
PASAf Avatar asked Feb 05 '13 14:02

PASAf


1 Answers

Problem:

The problem with your code is, that if you use the first attempt,

$bar[$i]->$n = $v;

a default empty object will be created for if you use the -> operator on a non existent array index. (NULL). You'll get a warning as this is a bad coding practice.

The second attempt

$bar[$i] = new stdClass;
$bar[$i]->$n = $v;

will simply fail as you overwrite $bar[$i] each loop.

Btw the code above won't work even with PHP5.3


Solution:

I would prefer the following code example because:

  • it works without warnings :)
  • it don't uses the inline initialization features like in your question. I think its is good coding practice to declare $bar explicitely as empty array() and to create the objects using: new StdClass().
  • it uses descriptive variable names help to understand what the code is doing.

code:

<?php

$foo = array(
  "somefield" => array("value1", "value2", "value3"),
  "anotherfield" => array("value1", "value2", "value3")
);

// create the $bar explicitely
$bar = array();

// use '{ }' to enclose foreach loops. Use descriptive var names
foreach($foo as $key => $values) {
    foreach($values as $index => $value) {
        // if the object has not already created in previous loop
        // then create it. Note, that you overwrote the object with a 
        // new one each loop. Therefore it only contained 'anotherfield'
        if(!isset($bar[$index])) {
            $bar[$index] = new StdClass();
        }
        $bar[$index]->$key = $value;
    }
}

var_dump($bar);
like image 159
hek2mgl Avatar answered Oct 02 '22 12:10

hek2mgl