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PhoneGap upload Image to server on form submit

I am facing problem here as in phonegap image is uploaded to the server once u select a picture.I don't want to upload image before submitting form. Image is uploaded automatically to server which is something i don't want.I want to upload image with the form, where form contains many more fields which is required to send along with image. What are the possible ways to submit with form?

<!DOCTYPE HTML >
<html>
<head>
<title>Registration Form</title>
<script type="text/javascript" charset="utf-8" src="phonegap-1.2.0.js"></script>
<script type="text/javascript" charset="utf-8">

    // Wait for PhoneGap to load
    document.addEventListener("deviceready", onDeviceReady, false);

    // PhoneGap is ready
    function onDeviceReady() {
// Do cool things here...
    }

    function getImage() {
        // Retrieve image file location from specified source
        navigator.camera.getPicture(uploadPhoto, function(message) {
alert('get picture failed');
},{
quality: 50,
destinationType: navigator.camera.DestinationType.FILE_URI,
sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY
});}
    function uploadPhoto(imageURI) {
        var options = new FileUploadOptions();
        options.fileKey="file";
        options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
        options.mimeType="image/jpeg";

        var params = new Object();
        params.value1 = "test";
        params.value2 = "param";

        options.params = params;
        options.chunkedMode = false;

        var ft = new FileTransfer();
        ft.upload(imageURI, "http://yourdomain.com/upload.php", win, fail, options);
    }

    function win(r) {
        console.log("Code = " + r.responseCode);
        console.log("Response = " + r.response);
        console.log("Sent = " + r.bytesSent);
        alert(r.response);
    }

    function fail(error) {
        alert("An error has occurred: Code = " = error.code);
    }

    </script>
</head>
<body>
<form id="regform">
<button onclick="getImage();">select Avatar<button>
<input type="text" id="firstname" name="firstname" />
<input type="text" id="lastname" name="lastname" />
<input type="text" id="workPlace" name="workPlace" class="" />
<input type="submit" id="btnSubmit" value="Submit" />
</form>
</body>
</html>
like image 786
Navneeth Avatar asked Mar 21 '14 12:03

Navneeth


2 Answers

Create two functions you can call separately. One function for just getting the image, and another function to upload the image.

You can do something like below.

<!DOCTYPE html>
<html>
  <head>
    <title>Submit form</title>

    <script type="text/javascript" charset="utf-8" src="cordova.js"></script>
    <script type="text/javascript" charset="utf-8">

    var pictureSource;   // picture source
    var destinationType; // sets the format of returned value

    // Wait for device API libraries to load
    //
    document.addEventListener("deviceready",onDeviceReady,false);

    // device APIs are available
    //
    function onDeviceReady() {
        pictureSource = navigator.camera.PictureSourceType;
        destinationType = navigator.camera.DestinationType;
    }


    // Called when a photo is successfully retrieved
    //
    function onPhotoURISuccess(imageURI) {

        // Show the selected image
        var smallImage = document.getElementById('smallImage');
        smallImage.style.display = 'block';
        smallImage.src = imageURI;
    }


    // A button will call this function
    //
    function getPhoto(source) {
      // Retrieve image file location from specified source
      navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
        destinationType: destinationType.FILE_URI,
        sourceType: source });
    }

    function uploadPhoto() {

        //selected photo URI is in the src attribute (we set this on getPhoto)
        var imageURI = document.getElementById('smallImage').getAttribute("src");
        if (!imageURI) {
            alert('Please select an image first.');
            return;
        }

        //set upload options
        var options = new FileUploadOptions();
        options.fileKey = "file";
        options.fileName = imageURI.substr(imageURI.lastIndexOf('/')+1);
        options.mimeType = "image/jpeg";

        options.params = {
            firstname: document.getElementById("firstname").value,
            lastname: document.getElementById("lastname").value,
            workplace: document.getElementById("workplace").value
        }

        var ft = new FileTransfer();
        ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
    }

    // Called if something bad happens.
    //
    function onFail(message) {
      console.log('Failed because: ' + message);
    }

    function win(r) {
        console.log("Code = " + r.responseCode);
        console.log("Response = " + r.response);
        //alert("Response =" + r.response);
        console.log("Sent = " + r.bytesSent);
    }

    function fail(error) {
        alert("An error has occurred: Code = " + error.code);
        console.log("upload error source " + error.source);
        console.log("upload error target " + error.target);
    }

    </script>
  </head>
  <body>
    <form id="regform">
        <button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">Select Photo:</button><br>
        <img style="display:none;width:60px;height:60px;" id="smallImage" src="" />

        First Name: <input type="text" id="firstname" name="firstname"><br>
        Last Name: <input type="text" id="lastname" name="lastname"><br>
        Work Place: <input type="text" id="workplace" name="workPlace"><br>
        <input type="button" id="btnSubmit" value="Submit" onclick="uploadPhoto();">
    </form>
  </body>
</html>
like image 146
edg Avatar answered Oct 13 '22 02:10

edg


You're already sending custom fields in your example.

var params = new Object();
params.value1 = "test";
params.value2 = "param";

options.params = params;

Just populate params with your form fields.

like image 31
Paolo Casciello Avatar answered Oct 13 '22 01:10

Paolo Casciello