I'm writing an application for iPad using PhoneGap and I would like to load an external URL without triggering Safari or using internal web browser like ChildBrowser.
I'm using the PhoneGap iPad/iPhone sample project and I tried different approaches. In the onBodyLoad() function I added:
window.location.href('http://www.wordreference.com');
but this line opens the link using a new Safari window.From that point is not possible to come back in PhoneGap
Afterwards, I tried with an AJAX request substituting the content of the page using document.write
function loadHTML(url, timeout) { if (timeout == undefined) timeout = 10000; var req = new XMLHttpRequest(); var timer = setTimeout(function() { try { req.abort(); } catch(e) {} navigator.notification.loadingStop(); },timeout); req.onreadystatechange = function() { if (req.readyState == 4) { if (req.status < 300) { clearTimeout(timer); var html = req.responseText; //just a debug print alert(html); document.write(html); } navigator.notification.loadingStop(); delete req; } }; req.open('GET', url, true); req.send(); }
Now, calling from inside onBodyLoad():
loadHTML('http://www.wordreference.com',10000);
Opens the link in the PhoneGap Container,which is fine. The point is that I want to load a dynamic page written in Python
loadHTML('http://www.mysite.com/cgi-bin/index.py',10000)
At this point Safari is not called but a black page in the PhoneGap container is displayed!! I want to point out that the link is perfectly working if I type it in Safari( I cannot report it for privacy issues).
Could be it a problem related to some kind of needed permission???
I found something similar relative to PhoneGap for BlackBerry and the proposed solution was to modify a config.xml file with
<access subdomains="true" uri="http://www.mysite.com/" />
I tried to add this tag directly in my index.html but it doesn't work.
Is there any similar approach for iPhone??
Thanks a lot
I think I've found the solution,
in the PhoneGap Application Delegate .m file {YourProject}AppDelegate.m, modify the method:
- (BOOL)webView:(UIWebView *)theWebView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType { return [super webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType]; }
with
- (BOOL)webView:(UIWebView *)theWebView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType { NSURL *url = [request URL]; if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"]) { return YES; } else { return [ super webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType ]; } }
This will open all the external links within the PhoneGap container!!!
ps. Around you will find references to this link but I think it doesn't work for app written using the 0.9.5 version,since Safari gets opened for external links by default.
For people having this problem in Android:
I don't know about earlier versions, but in PhoneGap 1.1.0 you can create a file called res/xml/phonegap.xml and list the domains which should not be opened in the external browser.
From DroidGap.java:
/** * Load PhoneGap configuration from res/xml/phonegap.xml. * Approved list of URLs that can be loaded into DroidGap * <access origin="http://server regexp" subdomains="true" /> * Log level: ERROR, WARN, INFO, DEBUG, VERBOSE (default=ERROR) * <log level="DEBUG" /> */ private void loadConfiguration() { [...]
Example phonegap.xml:
<?xml version="1.0" encoding="UTF-8"?> <phonegap> <access origin="http://stackoverflow.com" subdomains="true" /> </phonegap>
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