I would like to match any Num from part of a text string. So far, this (stolen from from https://docs.perl6.org/language/regexes.html#Best_practices_and_gotchas) does the job...
my token sign { <[+-]> }
my token decimal { \d+ }
my token exponent { 'e' <sign>? <decimal> }
my regex float {
<sign>?
<decimal>?
'.'
<decimal>
<exponent>?
}
my regex int {
<sign>?
<decimal>
}
my regex num {
<float>?
<int>?
}
$str ~~ s/( <num>? \s*) ( .* )/$1/;
This seems like a lot of (error prone) reinvention of the wheel. Is there a perl6 trick to match built in types (Num, Real, etc.) in a grammar?
If you can make reasonable assumptions about the number, like that it's delimited by word boundaries, you can do something like this:
regex number {
« # left word boundary
\S+ # actual "number"
» # right word boundary
<?{ defined +"$/" }>
}
The final line in this regex stringifies the Match ("$/"
), and then tries to convert it to a number (+
). If it works, it returns a defined value, otherwise a Failure
. This string-to-number conversion recognizes the same syntax as the Perl 6 grammar. The <?{ ... }>
construct is an assertion, so it makes the match fail if the expression on the inside returns a false value.
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