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Does it also match empty string, or only non-empty strings? I have been trying to find a reference unsuccesfully.
865
The SQL LIKE Operator The percent sign (%) represents zero, one, or multiple characters. The underscore sign (_) represents one, single character.
Since ; is used to terminate an individual statement, they need a way to indicate the procedure/trigger is done - and this is where the delimiter command comes into play. On the first row, we define the following trigger will be delimited (ended) by the $$ sequence.
The percent sign ( % ) is a symbol used in the English language as an abbreviation for the word "percent." Percent is a mathematical term meaning one part of a hundred.
Following is the query to add a percentage (%) sign to each value at the end while using MySQL SELECT statement − mysql> select StudentId,StudentName,concat (StudentScore,'%') AS StudentScore from DemoTable; This will produce the following output −
To add percentage sign at the end, use CONCAT () function. Let us first create a table − mysql> create table DemoTable ( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, StudentName varchar (100), StudentScore int ); Query OK, 0 rows affected (0.68 sec)
To calculate percentage of column in MySQL, you can simply cross join the sum () of sale column with the original table. If you want to add a where clause to filter your data, you need to place it after the CROSS JOIN, as shown below.
How to Calculate Percentage of Column in MySQL using CROSS JOIN To calculate percentage of column in MySQL, you can simply cross join the sum () of sale column with the original table.
Why don't you try it yourself and see? At any rate, here are the docs you were looking for:
With LIKE you can use the following two wildcard characters in the pattern.
Character Description % Matches any number of characters, even zero characters _ Matches exactly one character
http://dev.mysql.com/doc/refman/5.6/en/string-comparison-functions.html#operator_like
154
Have a look at the following demo to explain
CREATE TABLE Table1(
ID INT AUTO_INCREMENT,
Val VARCHAR(50),
PRIMARY KEY (id)
);
INSERT INTO Table1 (Val) SELECT 'TEST';
INSERT INTO Table1 (Val) SELECT '';
SELECT *
FROM Table1
WHERE Val LIKE '%'
Also from 12.5.1. String Comparison Functions
% Matches any number of characters, even zero characters
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